Delphi map/mat sensor

[RobertISaar]

for IAT, semi-easy, since you could always just modify the transfer table in the calibration.

the MAP..... not as easy. you could use the signal natively, but expect to have to retune nearly the entire VE and spark table. otherwise, a patch would be required to more or less emulate a GM 1BAR sensor.

[907 Chevy]

Ah, I see. Well, redoing the entire VE table is really no biggy since I'm starting over from scratch with a stock bin anyways. It's going to have to be done either way.

[907 Chevy]

Quick question: How do I bench test sensors? I was just going use a car battery regulated down to 5v as a voltage supply, however the voltage regulator I found at RadioShack says it can put out up to 1 amp of current. Is that much current going to cook my map sensor?

[907 Chevy]

Doh! It's the circuit that determines amperage draw isn't it? The regulator has nothing to do with it... Dumb question sorry, I've never actually had to think about this kinda stuff

[RobertISaar]

yeah, the components connected to the regulated source determine draw. a MAP sensor usually has between 5K and 50K of resistance, so VERY little current is consumed. you'll want to verify with a multimeter just to be certain though.

[EagleMark]

Being a Delphi I have high hopes.

The MAT would be Ohms just like an IAT or CTS. Then used in 256 bit in PCM and there's a table for that in $0D.

The MAP is a 5 volt reference, (Specs from link) 0.25 to 4.75 VDC depending on MAP/Vacuum and there's a chart in the link but no real specs, or do I know of exact specs for regualr MAP sensor?

But looks like four sensors and some good for boost. Differant styles to, one with bolt hole so I'm guessing it would be a boosted application.
• 15 kPa to 102 kPa Normally Aspirated
• 12.5 kPa to 115 kPa Would work?
• 20 kPa to 250 kPa 2 bar
• 10 kPa to 350 kPa 3 bar

EDIT: Here's some good info on GM MAP sensors:
http://www.robietherobot.com/storm/mapsensor.htm

[gregs78cam]

I don't remember where I found it, but I have used this(Volts/Vacuum/Kpa), and it pretty much matches up to what Mark posted.

[EagleMark]

Nice!

When you get that close remember that Barometric pressure has to be accounted for.